5(3x-2)^2+7=17

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Solution for 5(3x-2)^2+7=17 equation: 



5(3x-2)^2+7=17

We move all terms to the left:

5(3x-2)^2+7-(17)=0

We add all the numbers together, and all the variables

5(3x-2)^2-10=0

We move all terms containing x to the left, all other terms to the right

5(3x-2)^2=10

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